AIIMS2019Chemistry-Chemical Equilibrium

AIIMS 2019 Chemistry Equilibrium Constants MCQ Question

Type: MCQ-conceptual-Medium-Class 11

For the forward chemical reaction, A + B ⇌ C, The rate of reaction is, Kₑ = [C]/[A][B] And for reverse chemical reaction, C ⇌ A + B, The rate of reaction is, Kₑ = [A][B]/[C] Thus, Kₑ = 1/Kₑ

Correct Answer

Option C

Detailed Explanation

In the context of chemical equilibrium, the equilibrium constant KeK_e for the forward reaction A+BCA + B \rightleftharpoons C is given by Ke=[C][A][B]K_e = \frac{[C]}{[A][B]}. For the reverse reaction CA+BC \rightleftharpoons A + B, the equilibrium constant is Ke=[A][B][C]K_e' = \frac{[A][B]}{[C]}. Since the reverse reaction is simply the inverse of the forward reaction, it follows that Ke=1KeK_e' = \frac{1}{K_e}, confirming that KeKe=1K_e \cdot K_e' = 1. The other options are not relevant as they do not provide any additional information or correct interpretations of the equilibrium constants.

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