AIIMS2018Chemistry-Equilibrium

AIIMS 2018 Chemistry Acid-Base Equilibria MCQ Question

Type: MCQ-numerical-Medium-Class 11

Calculate ionisation constant for pyridinium chloride, Given that H+\text{H}^+ ion concentration is 3.6×104 M3.6 \times 10^{-4}\text{ M} and its concentration is 0.02 M0.02\text{ M}.

A

6.48×1026.48 \times 10^{-2}

B

6×1066 \times 10^{-6}

C

6×1086 \times 10^{-8}

D

12×10812 \times 10^{-8}

Correct Answer

Option A

Detailed Explanation

The calculation provided indicates that the dissociation constant KaK_a for the acid is derived from the formula Ka=[H+]2CK_a = \frac{[H^+]^2}{C}, where [H+][H^+] is the concentration of hydrogen ions and CC is the initial concentration of the acid. Substituting the given values, Ka=(3.6×104)20.02=6.48×106K_a = \frac{(3.6 \times 10^{-4})^2}{0.02} = 6.48 \times 10^{-6}, confirms that the calculated KaK_a aligns with the expected dissociation behavior of weak acids. Since the other options are not applicable or do not provide relevant information, they are not considered correct in this context.

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