AIIMS 2019 Chemistry Rate Laws MCQ Question
A(g) → 2B(g) + C(g) Initial: P₀ 0 0 P₀ - P 2P P Pₜ = P₀ - P + 2P + P = P₀ + 2P Therefore, P = (Pₜ + P₀) / 2 Apply the expression shown below to calculate rate constant. k = (2.303 / t) log [P₀ / (P₀ - P)] Substitute the value of P in above equation.
k = log
k = log
k = log
Correct Answer
Detailed Explanation
To derive the rate constant for the reaction , we substitute into the rate equation . This substitution leads to option B: , which correctly accounts for the stoichiometry of the reaction and the changes in pressure.
Options A and C are incorrect because they misrepresent the relationship between , , and , leading to invalid logarithmic expressions that do not accurately reflect the system's behavior. Understanding these relationships is crucial for correctly applying the integrated rate laws in chemical kinetics.
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