AIIMS2019Chemistry-Chemical Kinetics

AIIMS 2019 Chemistry First Order Reactions MCQ Question

Type: MCQ-numerical-Medium-Class 12

Find out time period of 1st1^{st} order reaction. When reaction complete 2/3rd3^{rd}. If the value of rate constant is 4.3×10⁻⁴

A

0.0025×10³ sec

B

0.25×10³ sec

C

0.025×10³ sec

D

2.5×10³ sec

Correct Answer

Option D

Detailed Explanation

For a first-order reaction, the relationship between the rate constant (k), time (t), and the fraction of reaction completed can be described by the equation:

t=2.303klog([A]0[A])t = \frac{2.303}{k} \log \left( \frac{[A]_0}{[A]} \right)

When 2/3 of the reaction is complete, 1/3 of the reactant remains, so [A]=13[A]0[A] = \frac{1}{3}[A]_0. Substituting this into the equation gives:

t=2.3034.3×104log(3)2.5×103 sect = \frac{2.303}{4.3 \times 10^{-4}} \log(3) \approx 2.5 \times 10^3 \text{ sec}

Thus, option D is correct. The other options are incorrect because they do not match the calculated time period based on the provided rate constant and the fraction of the reaction completed.

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