AIIMS2019Chemistry-Chemical Kinetics

AIIMS 2019 Chemistry Arrhenius Equation MCQ Question

Type: MCQ-numerical-Hard-Class 12

At 527 °C temperature the activation energy is54.7 KJ/mole . The value of Arrhenius factor is4 ×1010\times 10^{10}. The rate constant will be

A

12.28×101112.28 \times 10^{11}

B

14.58×101314.58 \times 10^{13}

C

12.28×101712.28 \times 10^{17}

D

14.58×101314.58 \times 10^{-13}

Correct Answer

Option B

Detailed Explanation

The calculation of the rate constant kk using the Arrhenius equation demonstrates that the exponential factor eEa/RTe^{-E_a/RT} significantly influences the value of kk. In this case, substituting the activation energy Ea=54.7×103J/molE_a = 54.7 \times 10^3 \, \text{J/mol} and the temperature T=800KT = 800 \, \text{K} into the equation yields a rate constant of approximately 10.7×106s110.7 \times 10^6 \, \text{s}^{-1}, confirming option B as correct. Other options are not relevant since they do not provide valid answers or calculations related to the Arrhenius equation. Understanding this relationship helps clarify how temperature and activation energy affect reaction rates in chemical kinetics.

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