AIIMS 2019 Chemistry Arrhenius Equation MCQ Question
lnk = 10 - 69(KJ)/RT ……(i)
k = Ae^(-Ea/RT)
ln k = ln A - Ea/RT ……(ii)
Comparison of equation (i) and(ii)
Ea is 69.
The rate constants in Arrhenius equation at two different temperatures are expressed as stated below.
ln k₁ = ln A - Ea/RT₁
ln k₂ = ln A - Ea/RT₂
ln k₂ - ln k₁ = Ea/R (1/T₁ - 1/T₂)
log 2k₁/k₁ = 69/2.303×8.314 (T₂ - 300/300T₂)
Correct Answer
Detailed Explanation
Option B, , correctly represents the Arrhenius equation at temperature , where is the activation energy, and is the universal gas constant. This equation shows how the rate constant is related to the pre-exponential factor and the temperature .
Option A is incorrect because it specifies instead of . Option C is a rearrangement of the Arrhenius equation that is valid but does not directly express as required. Option D introduces an unnecessary logarithmic transformation and does not accurately represent the relationship between the rate constants and temperatures in the context of the Arrhenius equation.
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