AIIMS2019Chemistry-Chemical Kinetics

AIIMS 2019 Chemistry Arrhenius Equation MCQ Question

Type: MCQ-conceptual-Medium-Class 12

lnk = 10 - 69(KJ)/RT ……(i)

k = Ae^(-Ea/RT)

ln k = ln A - Ea/RT ……(ii)

Comparison of equation (i) and(ii)

Ea is 69.

The rate constants in Arrhenius equation at two different temperatures are expressed as stated below.

A

ln k₁ = ln A - Ea/RT₁

B

ln k₂ = ln A - Ea/RT₂

C

ln k₂ - ln k₁ = Ea/R (1/T₁ - 1/T₂)

D

log 2k₁/k₁ = 69/2.303×8.314 (T₂ - 300/300T₂)

Correct Answer

Option B

Detailed Explanation

Option B, lnk2=lnAEaRT2\ln k_2 = \ln A - \frac{E_a}{RT_2}, correctly represents the Arrhenius equation at temperature T2T_2, where EaE_a is the activation energy, and RR is the universal gas constant. This equation shows how the rate constant k2k_2 is related to the pre-exponential factor AA and the temperature T2T_2.

Option A is incorrect because it specifies T1T_1 instead of T2T_2. Option C is a rearrangement of the Arrhenius equation that is valid but does not directly express lnk2\ln k_2 as required. Option D introduces an unnecessary logarithmic transformation and does not accurately represent the relationship between the rate constants and temperatures in the context of the Arrhenius equation.

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