AIIMS 2018 Chemistry Activation Energy MCQ Question

The equation derived from the ratio of reaction rates shows that the difference in activation energies, $E_b - E_a = RT \ln 2$, can be rearranged to express $E_a - E_b$ as $-RT \ln 2$. This indicates that the activation energy $E_a$ is lower than $E_b$ by $RT \ln 2$, confirming option B as correct. Other options are not applicable in this context, as they do not provide relevant information or calculations related to the activation energies or their relationship. Understanding the relationship between activation energy and reaction rates is crucial for grasping the principles of chemical kinetics.