Back to Practice
AIIMS2018Chemistry-Chemical Equilibrium

AIIMS 2018 Chemistry Equilibrium Concentrations MCQ Question

Type: MCQ-numerical-Medium-Class 11

CH3−CH=CH−CH=N−CH3→LiAlH4What is final product?\text{CH}_3 - \text{CH} = \text{CH} - \text{CH} = \text{N} - \text{CH}_3 \xrightarrow{\text{LiAlH}_4} \text{What is final product?}

A

CH3−CH2−CH2−CH2−NH−CH3\text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{NH} - \text{CH}_3

B

CH3−CH=CH−CH2−NH−CH3\text{CH}_3 - \text{CH} = \text{CH} - \text{CH}_2 - \text{NH} - \text{CH}_3

C

CH3−CH2−CH2−CH=N−CH3\text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{CH} = \text{N} - \text{CH}_3

D

CH3−CH=CH−CH2−OH\text{CH}_3 - \text{CH} = \text{CH} - \text{CH}_2 - \text{OH}

Correct Answer

Option B

Detailed Explanation

To find the equilibrium concentration of I₂ (denoted as x), we start with the initial concentration of ICl at 0.6 M. The stoichiometry of the reaction shows that for every 2 moles of ICl that react, 1 mole of I₂ is produced. Thus, at equilibrium, the concentration of I₂ is given by x = (0.6 - 2x)/2. Solving this equation leads to x = 0.256 M, confirming option B as the correct answer. Other options are incorrect because they do not satisfy the stoichiometric relationship or the equilibrium condition derived from the initial concentrations.

Found an issue with this question?

Related Questions

Explore More Questions

All Chemistry QuestionsEquilibrium QuestionsAIIMS 2018 PYQ