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AIIMS2019Chemistry-Chemical Bonding

AIIMS 2019 Chemistry VSEPR Theory MCQ Question

Type: MCQ-conceptual-Medium-Class 11

The correct order of S–S\text{S--S} bond length in following oxyanions is:

(I) S2O42−(II) S2O52−(III) S2O62−\text{(I) S}_2\text{O}_4^{2-}\quad \text{(II) S}_2\text{O}_5^{2-}\quad \text{(III) S}_2\text{O}_6^{2-}

A

I>II>III\text{I} > \text{II} > \text{III}

B

I>III>II\text{I} > \text{III} > \text{II}

C

III>II>I\text{III} > \text{II} > \text{I}

D

III>I>II\text{III} > \text{I} > \text{II}

Correct Answer

Option A

Detailed Explanation

The order of S−S bond lengths is influenced by the type of repulsion between electron pairs in the bonding molecular orbitals. According to the given repulsion hierarchy (L.P−L.P > L.P−B.P > B.P−B.P), lone pair-lone pair (L.P−L.P) repulsion is the strongest, leading to a shorter bond length in species with more lone pairs. Thus, species I, with the highest lone pair repulsion, has the shortest S−S bond length, followed by II and then III, making the order I > II > III correct. Options B, C, and D incorrectly suggest different relationships that do not align with the established repulsion hierarchy.

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