One mole of magnesium in the vapour state absorbed 1200 kJ mol⁻¹ energy. If the first and second ionisation energies of Mg are 750 and 1450 kJ mol⁻¹ respectively, the final composition of the mixture is
A
86% Mg⁺ + 14% Mg²⁺
B
69% Mg⁺ + 31% Mg²⁺
C
14% Mg⁺ + 86% Mg²⁺
D
31% Mg⁺ + 69% Mg²⁺

Question

One mole of magnesium in the vapour state absorbed 1200 kJ mol⁻¹ energy. If the first and second ionisation energies of Mg are 750 and 1450 kJ mol⁻¹ respectively, the final composition of the mixture is

A

86% Mg⁺ + 14% Mg²⁺

B

69% Mg⁺ + 31% Mg²⁺

C

14% Mg⁺ + 86% Mg²⁺

D

31% Mg⁺ + 69% Mg²⁺

Accepted Answer

69% Mg⁺ + 31% Mg²⁺

Answer

86% Mg⁺ + 14% Mg²⁺

Answer

14% Mg⁺ + 86% Mg²⁺

Answer

31% Mg⁺ + 69% Mg²⁺

AIIMS 2015 Chemistry Ionization Energy MCQ Question

Correct Answer

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