AIIMS2017Chemistry-Amines

AIIMS 2017 Chemistry Hofmann Bromamide Reaction MCQ Question

Type: MCQ-conceptual-Medium-Class 12

Assertion (A): When acetamide reacts with NaOH\text{NaOH} and Br2\text{Br}_2, methyl amine is formed.

Reason (R): The reaction occurs through the intermediate formation of an isocyanate.

A

Both Assertion and Reason are true and Reason is the correct explanation of Assertion.

B

Both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

C

Assertion is true but Reason is false.

D

Both Assertion and Reason are false.

Correct Answer

Option A

Detailed Explanation

When acetamide (CH₃CONH₂) reacts with Br₂ and NaOH, it undergoes a halogenation reaction leading to the formation of methyl amine (CH₃NH₂) and sodium carbonate (Na₂CO₃) as byproducts. This reaction involves the deamination of acetamide, where the amine group is retained, and the carbonyl group is converted into a carboxylate, which subsequently forms Na₂CO₃ upon reaction with NaOH.

Options B, C, and D are incorrect because they suggest the formation of sodium bromide (NaBr), sodium hydroxide (NaOH), or sodium sulfate (Na₂SO₄), none of which are products of the reaction between acetamide, Br₂, and NaOH.

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