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AIIMS2018Botany-Cellular Respiration

AIIMS 2018 Botany Krebs Cycle MCQ Question

Type: MCQ-conceptual-Medium-Class 11

Which is the correct link reaction?

A

Pyruvic acid+NAD++Co-A→Mg2+Pyruvate dehydrogenaseAcetyl Co-A+NADH⋅H++CO2\text{Pyruvic acid} + \text{NAD}^+ + \text{Co-A} \xrightarrow[\text{Mg}^{2+}]{\text{Pyruvate dehydrogenase}} \text{Acetyl Co-A} + \text{NADH}\cdot\text{H}^+ + \text{CO}_2

B

Pyruvic acid+FAD++Co-A→Mg2+Pyruvate dehydrogenaseAcetyl Co-A+FADH⋅H++CO2\text{Pyruvic acid} + \text{FAD}^+ + \text{Co-A} \xrightarrow[\text{Mg}^{2+}]{\text{Pyruvate dehydrogenase}} \text{Acetyl Co-A} + \text{FADH}\cdot\text{H}^+ + \text{CO}_2

C

Pyruvic acid+NADP++Co-A→Mg2+Pyruvate dehydrogenaseAcetyl Co-A+NADPH⋅H++CO2\text{Pyruvic acid} + \text{NADP}^+ + \text{Co-A} \xrightarrow[\text{Mg}^{2+}]{\text{Pyruvate dehydrogenase}} \text{Acetyl Co-A} + \text{NADPH}\cdot\text{H}^+ + \text{CO}_2

D

Pyruvic acid+NAD++Co-A→Mg2+Pyruvate dehydrogenaseAcetyl Co-A+NADH⋅H+\text{Pyruvic acid} + \text{NAD}^+ + \text{Co-A} \xrightarrow[\text{Mg}^{2+}]{\text{Pyruvate dehydrogenase}} \text{Acetyl Co-A} + \text{NADH}\cdot\text{H}^+

Correct Answer

Option A

Detailed Explanation

Option A is correct because the reaction described represents the conversion of pyruvic acid into acetyl CoA, a crucial step in cellular respiration. This process involves the decarboxylation of pyruvic acid, resulting in the production of NADH, H⁺, and CO₂, while CoA is added to form acetyl CoA. Other options are incorrect as they likely do not represent the accurate biochemical pathway or may include incorrect reactants or products that do not align with the established metabolic processes. Understanding this reaction is essential for grasping how energy is harvested from glucose during aerobic respiration.

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